tag:blogger.com,1999:blog-38193052.post3551315152577812030..comments2024-03-20T08:57:17.447-03:00Comments on Jornalheiros: Xadrez - Mate em 3! (Mikhail Marandyuk)PC Filhohttp://www.blogger.com/profile/16547063456626761789noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-38193052.post-90421104686927285042016-01-21T10:24:58.430-02:002016-01-21T10:24:58.430-02:00There are also the variations 1 ... Nxd2 2 Bxe6 ~ ...There are also the variations <b>1 ... Nxd2 2 Bxe6 ~ 3 Ne2</b>; and <b>1 ... Ng1 2 Rxe6 ~ 3 Be3</b>.jrh150482https://www.blogger.com/profile/10502831081969372299noreply@blogger.comtag:blogger.com,1999:blog-38193052.post-11123635161020531702016-01-21T10:16:54.643-02:002016-01-21T10:16:54.643-02:00I think I have it now, Paulo.
The key is the squa...I think I have it now, Paulo.<br /><br />The key is the square-clearing <b>1 Kg8!</b>, threatening 2 f8(N), which threatens 3 Nfe6 with the variations 2 ... Rxe5 3 Be3 and 2 ... Bd5 3 Ne2. The full-length variations feature distant self-blocks: <b>1 ... Rf5 2 Be3+ Kxe5 3 Rxe6</b>; and <b>1 ... Bc6 2 Ne2+ Kd5 3 Bxe6</b>. There are two short mating lines, and the self-block also presents itself here: 1 ... Rxe5 2 Be3#; and 1 ... Bd5 2 Ne2#.<br /><br />In addition to the self-blocks, there is also an "avoidance of self-injury" theme here, in which any king move makes the same threat as the key, but only the key works: 1 Ke7/Kg7? Nh4! [2 f8(N)? Nf5+!]; 1 Ke8? Bc6! (pins the d7-bishop and thus disables Bxe6).<br /><br />Quite a nice puzzle, and a highly unified one at that.jrh150482https://www.blogger.com/profile/10502831081969372299noreply@blogger.comtag:blogger.com,1999:blog-38193052.post-34800262097478323762016-01-21T10:13:51.239-02:002016-01-21T10:13:51.239-02:00Este comentário foi removido pelo autor.jrh150482https://www.blogger.com/profile/10502831081969372299noreply@blogger.comtag:blogger.com,1999:blog-38193052.post-84027220020590008782016-01-19T16:21:14.852-02:002016-01-19T16:21:14.852-02:00I believe you are almost solving it, Jake. :)I believe you are almost solving it, Jake. :)PC Filhohttps://www.blogger.com/profile/16547063456626761789noreply@blogger.comtag:blogger.com,1999:blog-38193052.post-8939672712718771352016-01-19T14:38:52.892-02:002016-01-19T14:38:52.892-02:00I haven't solved it yet, but I have identified...I haven't solved it yet, but I have identified the following set variations:<br /><br />1 ... Rxe5/Nxe5 2 Be3#<br />1 ... Bd5 2 Ne2#<br />1 ... Bc6 2 Ne2+ Kd5 3 Bxe6#<br /><br />(Interestingly enough, the black move at the beginning of each of these is a self-block.)jrh150482https://www.blogger.com/profile/10502831081969372299noreply@blogger.com